Post by flance741 on Jan 5, 2018 17:32:50 GMT
Lets suppose we have a pair of binary black holes with a couple of assumptions:
Black holes are similar in mass
Black hole event horizons cross
Black holes are relatively large, to minimize spaghettification
(these assumptions are not required, they just make the math for the path simpler, and pronounce the result)
Starting at one side of the binary pair, we aim to fly our rocket ship straight between the two, along the axis upon the two black holes rotate upon. (See image for clarification)
As the rocket ship draws near the point at which both event horizon's cross, the rocket's velocity approaches C. Upon crossing the event horizon, rules that exist in our universe no longer apply, and the rocket ship continues to accelerate passed C, until it reaches a critical point. The critical point is the location along the path of the rocket that intersects with the line of shortest path between the two black holes. At this point the rocket ship achieves its maximum velocity, the value of which is determined by the mass of the black holes. Just like as you drive your car down into a valley, the rocket ship has picked up a forward moving inertia caused by the dual pulls of gravity, which have equated to a single net pull between the two. At the critical point, the rocket has built up enough momentum to carry itself straight out of the event horizon out the other end, just as at the bottom of the valley, your car has built up enough inertia to make it back up the next hill. As the rocket transverses out of the event horizon on the other end of the binary pair, it mirrors its corresponding speeds at all locations of its path when it initially plunged into the binary pair until it finally decelerates to its initial speed, prior to entering the binary pair.
Upon exiting the event horizon, the rocket ship has experienced a great slowdown in relative time, which can equate to jumping years into the future.